Substituting into the Original Equations

Oct 13, 2025 by orovajewels.com 15 views

Introduction

In mathematics, solving systems of equations is a fundamental concept that involves finding the values of variables that satisfy multiple equations simultaneously. In this article, we will consider a specific system of equations and analyze its solutions. The system consists of two equations involving quadratic terms, and our goal is to determine the number of solutions that this system has.

The System of Equations

The given system of equations is:

\begin{aligned} -\frac{1}{3} x^2 &= -\frac{5}{6} + \frac{1}{3} y^2 \\ 5y^2 &= \frac{25}{2} - 5x^2 \end{aligned}

Rearranging the Equations

To simplify the analysis, we can rearrange the equations to isolate the quadratic terms. Multiplying the first equation by 3, we get:

-x^2 = -\frac{5}{2} + y^2

Multiplying the second equation by 2, we get:

10y^2 = 25 - 10x^2

Simplifying the Equations

We can further simplify the equations by dividing both sides of the first equation by 2 and both sides of the second equation by 10. This gives us:

-\frac{1}{2} x^2 = -\frac{5}{4} + \frac{1}{2} y^2

y^2 = \frac{5}{2} - \frac{1}{2} x^2

Equating the Expressions

Now, we can equate the expressions for $y^2$ from the two simplified equations:

\frac{1}{2} y^2 = \frac{5}{4} - \frac{1}{2} x^2

Solving for $x^2$

We can solve for $x^2$ by multiplying both sides of the equation by 2:

y^2 = \frac{5}{2} - x^2

Substituting into the Original Equations

We can substitute this expression for $y^2$ into the original equations to eliminate the quadratic terms. Substituting into the first equation, we get:

-\frac{1}{3} x^2 = -\frac{5}{6} + \frac{1}{3} \left(\frac{5}{2} - x^2\right)

Simplifying this equation, we get:

-\frac{1}{3} x^2 = -\frac{5}{6} + \frac{5}{6} - \frac{1}{3} x^2

Analyzing the Result

The resulting equation is a contradiction, as it implies that $-\frac{1}{3} x^2 = 0$ . This means that there is no solution to the system of equations.

Conclusion

In conclusion, the system of equations has no solutions. This is because the equations are inconsistent, and there is no value of $x$ and $y$ that satisfies both equations simultaneously.

Final Answer

The final answer is A. Zero.

Introduction

The System of Equations

The given system of equations is:

\begin{aligned} -\frac{1}{3} x^2 &= -\frac{5}{6} + \frac{1}{3} y^2 \\ 5y^2 &= \frac{25}{2} - 5x^2 \end{aligned}

Rearranging the Equations

To simplify the analysis, we can rearrange the equations to isolate the quadratic terms. Multiplying the first equation by 3, we get:

-x^2 = -\frac{5}{2} + y^2

Multiplying the second equation by 2, we get:

10y^2 = 25 - 10x^2

Simplifying the Equations

We can further simplify the equations by dividing both sides of the first equation by 2 and both sides of the second equation by 10. This gives us:

-\frac{1}{2} x^2 = -\frac{5}{4} + \frac{1}{2} y^2

y^2 = \frac{5}{2} - \frac{1}{2} x^2

Equating the Expressions

Now, we can equate the expressions for $y^2$ from the two simplified equations:

\frac{1}{2} y^2 = \frac{5}{4} - \frac{1}{2} x^2

Solving for $x^2$

We can solve for $x^2$ by multiplying both sides of the equation by 2:

y^2 = \frac{5}{2} - x^2

Substituting into the Original Equations

We can substitute this expression for $y^2$ into the original equations to eliminate the quadratic terms. Substituting into the first equation, we get:

-\frac{1}{3} x^2 = -\frac{5}{6} + \frac{1}{3} \left(\frac{5}{2} - x^2\right)

Simplifying this equation, we get:

-\frac{1}{3} x^2 = -\frac{5}{6} + \frac{5}{6} - \frac{1}{3} x^2

Analyzing the Result

The resulting equation is a contradiction, as it implies that $-\frac{1}{3} x^2 = 0$ . This means that there is no solution to the system of equations.

Conclusion

In conclusion, the system of equations has no solutions. This is because the equations are inconsistent, and there is no value of $x$ and $y$ that satisfies both equations simultaneously.

Final Answer

The final answer is A. Zero.

Q&A: Solving the System of Equations

Q: What is the system of equations?

A: The system of equations is a set of two equations involving quadratic terms, which are:

\begin{aligned} -\frac{1}{3} x^2 &= -\frac{5}{6} + \frac{1}{3} y^2 \\ 5y^2 &= \frac{25}{2} - 5x^2 \end{aligned}

Q: How many solutions does the system have?

A: The system has no solutions. This is because the equations are inconsistent, and there is no value of $x$ and $y$ that satisfies both equations simultaneously.

Q: Why is the system inconsistent?

A: The system is inconsistent because the equations lead to a contradiction. When we substitute the expression for $y^2$ into the original equations, we get a result that implies $-\frac{1}{3} x^2 = 0$ , which is a contradiction.

Q: What is the significance of this result?

A: This result shows that the system of equations has no solutions, which means that there is no value of $x$ and $y$ that satisfies both equations simultaneously. This is an important concept in mathematics, as it highlights the importance of checking the consistency of a system of equations before attempting to solve it.

Q: How can we determine the number of solutions to a system of equations?

A: We can determine the number of solutions to a system of equations by checking the consistency of the equations. If the equations are consistent, then there may be one or more solutions. If the equations are inconsistent, then there are no solutions.

Q: What is the final answer to the problem?

A: The final answer is A. Zero, which means that the system of equations has no solutions.